The Möbius function $\mu$ is defined by $$\mu(n) = \begin{cases} 1 & \text{if } n = 1 \\ (-1)^r & \text{if } n \text{ is the product of } r \text{ distinct prime numbers} \\ 0 & \text{otherwise} \end{cases}$$ Show that $\mu * \mathbf{1} = \delta$.
The Möbius function $\mu$ is defined by
$$\mu(n) = \begin{cases} 1 & \text{if } n = 1 \\ (-1)^r & \text{if } n \text{ is the product of } r \text{ distinct prime numbers} \\ 0 & \text{otherwise} \end{cases}$$
Show that $\mu * \mathbf{1} = \delta$.