Define $a _ { n } = \left( 1 ^ { 2 } + 2 ^ { 2 } + \ldots + n ^ { 2 } \right) ^ { n }$ and $b _ { n } = n ^ { n } ( n ! ) ^ { 2 }$. Recall $n !$ is the product of the first $n$ natural numbers. Then,
(a) $a _ { n } < b _ { n }$ for all $n > 1$
(b) $a _ { n } > b _ { n }$ for all $n > 1$
(c) $a _ { n } = b _ { n }$ for infinitely many $n$
(d) none of the above.
(b). Take the $n$th root of $a _ { n }$ and $b _ { n }$ and use A.M. $\geq$ G.M.
Define $a _ { n } = \left( 1 ^ { 2 } + 2 ^ { 2 } + \ldots + n ^ { 2 } \right) ^ { n }$ and $b _ { n } = n ^ { n } ( n ! ) ^ { 2 }$. Recall $n !$ is the product of the first $n$ natural numbers. Then,\\
(a) $a _ { n } < b _ { n }$ for all $n > 1$\\
(b) $a _ { n } > b _ { n }$ for all $n > 1$\\
(c) $a _ { n } = b _ { n }$ for infinitely many $n$\\
(d) none of the above.