Let $f : (0,2) \cup (4,6) \rightarrow \mathbb{R}$ be a differentiable function. Suppose also that $f''(x) = 1$ for all $x \in (0,2) \cup (4,6)$. Which of the following is ALWAYS true?\\
(A) $f$ is increasing\\
(B) $f$ is one-to-one\\
(C) $f(x) = x$ for all $x \in (0,2) \cup (4,6)$\\
(D) $f(5.5) - f(4.5) = f(1.5) - f(0.5)$