A box $B _ { 1 }$ contains 1 white ball, 3 red balls and 2 black balls. Another box $B _ { 2 }$ contains 2 white balls, 3 red balls and 4 black balls. A third box $B _ { 3 }$ contains 3 white balls, 4 red balls and 5 black balls.
If 2 balls are drawn (without replacement) from a randomly selected box and one of the balls is white and the other ball is red, the probability that these 2 balls are drawn from box $B _ { 2 }$ is
(A) $\frac { 116 } { 181 }$
(B) $\frac { 126 } { 181 }$
(C) $\frac { 65 } { 181 }$
(D) $\frac { 55 } { 181 }$