If the lines $\frac{x-1}{2} = \frac{y+1}{3} = \frac{z-1}{4}$ and $\frac{x-3}{1} = \frac{y-k}{2} = \frac{z}{1}$ intersect, then $k$ is equal to (1) $\frac{2}{9}$ (2) $\frac{9}{2}$ (3) 0 (4) $-1$
If the lines $\frac{x-1}{2} = \frac{y+1}{3} = \frac{z-1}{4}$ and $\frac{x-3}{1} = \frac{y-k}{2} = \frac{z}{1}$ intersect, then $k$ is equal to\\
(1) $\frac{2}{9}$\\
(2) $\frac{9}{2}$\\
(3) 0\\
(4) $-1$