If the lines $\frac{x-2}{1} = \frac{y-3}{1} = \frac{z-4}{-k}$ and $\frac{x-1}{k} = \frac{y-4}{2} = \frac{z-5}{1}$ are coplanar, then $k$ can be (1) $-1$ or $-3$ (2) $-1$ or $3$ (3) $1$ or $-1$ (4) $0$ or $-3$
If the lines $\frac{x-2}{1} = \frac{y-3}{1} = \frac{z-4}{-k}$ and $\frac{x-1}{k} = \frac{y-4}{2} = \frac{z-5}{1}$ are coplanar, then $k$ can be\\
(1) $-1$ or $-3$\\
(2) $-1$ or $3$\\
(3) $1$ or $-1$\\
(4) $0$ or $-3$