What should be the order of arrangement of de-Broglie wavelength of electron $\lambda_{\mathrm{e}}$, an $\alpha$-particle $\lambda_{\alpha}$ and proton $\lambda_{\mathrm{p}}$ given that all have the same kinetic energy?\\
(1) $\lambda_{e} = \lambda_{p} = \lambda_{\alpha}$\\
(2) $\lambda_{\mathrm{e}} < \lambda_{\mathrm{p}} < \lambda_{\alpha}$\\
(3) $\lambda_{\mathrm{e}} > \lambda_{\mathrm{p}} > \lambda_{\alpha}$\\
(4) $\lambda_{\mathrm{e}} = \lambda_{\mathrm{p}} > \lambda_{\alpha}$