2. Do you regularly speak or hear the language at home? ◯ No \end{tabular}} & \hline & & \multirow[t]{5}{*}{
} \hline 63. Gov. \& Pol. & & \hline \multirow[b]{3}{*}{
| 64. Essay Choices |
| Fill in the ovals under the numbers of the essay questions you answered in this examination.[Figure] |
} & & \hline & & \hline & & \hline \end{tabular}
\begin{displayquote} SOLUTIONS AND SCORING GUIDES SECTION II 1988 AP CALCULUS AB EXAMINATION \end{displayquote}
The solutions to the free-response questions that follow are intended to illustrate the general level of detail expected of candidates, and the scoring standards indicate how points were awarded to the main aspects of the answers. However, approaches to a problem may vary and, even with the same approach, the written solutions may vary in the way that the different steps are presented. Within the framework of points indicated, the Readers exercise latitude in interpreting the correctness of the solutions.
For example, credit is sometimes awarded for steps not written down, if it is clear that the candidate must have taken those steps to arrive at the result indicated. However, candidates are advised to show their work in order to minimize the risk of not receiving credit for it. Further, if one part of a problem depends on a value obtained in a previous part, and that value is incorrect, full credit is awarded for the latter part if it is done correctly, even though an incorrect result may have been obtained.
Readers often worked with scoring guides more detailed than those presented here in order to award points for correct approaches or to subtract points for calculus or other mathematical errors. In addition, Readers sometimes had scoring guides available for common incorrect approaches that nevertheless revealed some understanding of the calculus involved. In this way, a high degree of consistency in grading is obtained.
1988 Calculus AB
- Let $f$ be the function given by $f ( x ) = \sqrt { x ^ { 4 } - 16 x ^ { 2 } }$.
(a) Find the domain of $f$.
(b) Describe the symmetry, if any, of the graph of $f$.
(c) Find $f ^ { \prime } ( x )$.
(d) Find the slope of the line normal to the graph of $f$ at $x = 5$.
(a) $x ^ { 4 } - 16 x ^ { 2 } \geq 0$
$$\begin{aligned}
& x ^ { 2 } \left( x ^ { 2 } - 16 \right) \geq 0 \\
& x ^ { 2 } \geq 16 \text { or } x = 0 \\
& | x | \geq 4 \text { or } x = 0
\end{aligned}$$
(b) Symmetric about the $y$-axis
(c) $f ^ { \prime } ( x ) = \frac { 1 } { 2 } \left( x ^ { 4 } - 16 x ^ { 2 } \right) ^ { - \frac { 1 } { 2 } } \left( 4 x ^ { 3 } - 32 x \right)$
$$= \frac { 2 x \left( x ^ { 2 } - 8 \right) } { | x | \sqrt { x ^ { 2 } - 16 } }$$
(d) $f ^ { \prime } ( 5 ) = \frac { 2 ( 5 ) ( 25 - 8 ) } { 5 \sqrt { 25 - 16 } }$
$$= \frac { 10 ( 17 ) } { 5 \sqrt { 9 } } = \frac { 170 } { 15 } = \frac { 34 } { 3 }$$
. slope of normal line is $- \frac { 3 } { 34 }$
(a) $\left\{ \begin{array} { l } 1 : \text { for radicand } \geq 0 \\ 1 : \text { for } | x | \geq 4 \\ 1 : \text { for } x = 0 \end{array} \right.$
(b) 1: for correct answer
(c) 3: for correct derivative
(d) $\quad \left\{ \begin{aligned} 1 : & \begin{array} { l } \text { for evaluating } f ^ { \prime } ( x ) \\ \\ \text { found in (c) at } x = 5 \end{array} \\ 1 : & \text { for slope of normal } \end{aligned} \right.$
2. A particle moves along the $x$-axis so that its velocity at any time $t \geqq 0$ is given by $v ( t ) = 1 - \sin ( 2 \pi t )$.
(a) Find the acceleration $a ( t )$ of the particle at any time $t$.
(b) Find all values of $t , 0 \leqq t \leqq 2$, for which the particle is at rest.
(c) Find the position $x ( t )$ of the particle at any time $t$ if $x ( 0 ) = 0$.
Solution
(a) $a ( t ) = v ^ { \prime } ( t )$
$$= - 2 \pi \cos ( 2 \pi t )$$
(b) $v ( t ) = 0$ $1 - \sin ( 2 \pi t ) = 0$ or $1 = \sin ( 2 \pi t )$ $2 \pi t = \frac { \pi } { 2 } + 2 k \pi$, where $k = 0 , \pm 1 , \pm 2 , \ldots$ and $0 \leqq t \leqq 2$ $\therefore t = \frac { 1 } { 4 }$ and $t = \frac { 5 } { 4 }$
(c) $x ( t ) = \int v ( t ) d t$
$$\begin{aligned}
& = \int [ 1 - \sin ( 2 \pi t ) ] d t \\
& = t + \frac { 1 } { 2 \pi } \cos ( 2 \pi t ) + C
\end{aligned}$$
$$\begin{aligned}
& x ( 0 ) = 0 = 0 + \frac { \cos ( 0 ) } { 2 \pi } + C \\
& \therefore x ( t ) = t + \frac { 1 } { 2 \pi } \cos ( 2 \pi t ) - \frac { 1 } { 2 \pi }
\end{aligned}$$
Distribution of Points
(a) 2: for correct differentiation of velocity
(b) $3 : \left\{ \begin{array} { l } 1 : \text { for } 1 - \sin ( 2 \pi t ) = 0 \\ 1 : \text { for } t = \frac { 1 } { 4 } \\ 1 : \text { for } t = \frac { 5 } { 4 } \end{array} \right.$
(c) $\quad$ 2: for correct antiderivative of $v ( t )$ 4: 1: for $x ( 0 ) = 0$ 1: for finding value of $C$