The threshold frequency of metal is $f _ { 0 }$. When the light of frequency $2 f _ { 0 }$ is incident on the metal plate, the maximum velocity of photoelectron is $v _ { 1 }$. When the frequency of incident radiation is increased to $5 f _ { 0 }$. the maximum velocity of photoelectrons emitted is $v _ { 2 }$. The ratio of $v _ { 1 }$ to $v _ { 2 }$ is:
(1) $\frac { v _ { 1 } } { v _ { 2 } } = \frac { 1 } { 2 }$
(2) $\frac { v _ { 1 } } { v _ { 2 } } = \frac { 1 } { 8 }$
(3) $\frac { v _ { 1 } } { v _ { 2 } } = \frac { 1 } { 16 }$
(4) $\frac { v _ { 1 } } { v _ { 2 } } = \frac { 1 } { 4 }$