A copper rod of mass m slides under gravity on two smooth parallel rails, with separation $l$ and set at an angle of $\theta$ with the horizontal. At the bottom, rails are joined by a resistance $R$. There is a uniform magnetic field $B$ normal to the plane of the rails, as shown in the figure. The terminal speed of the copper rod is:
[Figure](1) $\frac { \mathrm { mgR } \cos \theta } { \mathrm { B } ^ { 2 } l ^ { 2 } }$
(2) $\frac { \mathrm { mgR } \sin \theta } { \mathrm { B } ^ { 2 } l ^ { 2 } }$
(3) $\frac { \mathrm { mgR } \tan \theta } { \mathrm { B } ^ { 2 } l ^ { 2 } }$
(4) $\frac { \mathrm { mgR } \cot \theta } { \mathrm { B } ^ { 2 } l ^ { 2 } }$