jee-main 2021 Q28

jee-main · India · session4_27aug_shift1 Not Maths
The alternating current is given by, $i = \left\{\sqrt{42}\sin\left(\frac{2\pi}{T}t\right) + 10\right\}$ A. The R.M.S. value of this current is $\_\_\_\_$ A.
The alternating current is given by, $i = \left\{\sqrt{42}\sin\left(\frac{2\pi}{T}t\right) + 10\right\}$ A. The R.M.S. value of this current is $\_\_\_\_$ A.