The length of a wire becomes $l_1$ and $l_2$ when 100 N and 120 N tension are applied respectively. If $10l_2 = 11l_1$, then the natural length of wire will be $\frac{1}{x}l_1$. Here the value of $x$ is
The length of a wire becomes $l_1$ and $l_2$ when 100 N and 120 N tension are applied respectively. If $10l_2 = 11l_1$, then the natural length of wire will be $\frac{1}{x}l_1$. Here the value of $x$ is