If three helium nuclei combine to form a carbon nucleus then the energy released in this reaction is $\_\_\_\_$ $\times 10^{-2}\mathrm{~MeV}$. (Given $1\mathrm{~u} = 931\mathrm{~MeV}/\mathrm{c}^2$, atomic mass of helium $= 4.002603\mathrm{~u}$)
If three helium nuclei combine to form a carbon nucleus then the energy released in this reaction is $\_\_\_\_$ $\times 10^{-2}\mathrm{~MeV}$. (Given $1\mathrm{~u} = 931\mathrm{~MeV}/\mathrm{c}^2$, atomic mass of helium $= 4.002603\mathrm{~u}$)