$ABC$ triangle, AFD equilateral triangle, $[DE]$ // $[AB]$, $m ( \widehat { DFC } ) = x$
In the figure, $m \widehat { ( \mathrm { ACF } ) } = m \widehat { ( \mathrm { FCB } ) } = m \widehat { ( \mathrm { DEC } ) }$ and points $D$, $E$, $F$ lie on the sides of triangle ABC.
Accordingly, what is x in degrees?\
A) 20\
B) 25\
C) 30\
D) 35\
E) 40