Where $0 < x < \frac{\pi}{2}$,
$$\frac{1 + \tan x}{\cot x} \cdot \frac{\sin x - \cos x}{\sin x} = 2$$
if this holds, what is the value of $\sin x$?\\
A) $\frac{1}{3}$\\
B) $\frac{3}{5}$\\
C) $\frac{\sqrt{2}}{2}$\\
D) $\frac{\sqrt{3}}{2}$\\
E) $\frac{\sqrt{5}}{3}$