5 identical isosceles right triangles with right-angled side lengths of 1 unit are arranged as shown in Figure 1 such that their hypotenuses are on the same line and the vertices of adjacent triangles coincide.
Then triangle $ABC$ is rotated around point $A$ by some amount, and as shown in Figure 2, points B, C, and D become collinear.
Accordingly, what is the distance between points C and D in the final position in units?\\
A) 4\\
B) 5\\
C) 6\\
D) $3\sqrt{2}$\\
E) $4\sqrt{2}$