gaokao 2015 Q11

gaokao · China · beijing-arts 5 marks Sine and Cosine Rules Find a side or angle using the sine rule

In $\triangle ABC$, $a = 3$, $b = \sqrt { 6 }$, $\angle A = \frac { 2 \pi } { 3 }$, then $\angle B =$

In $\triangle ABC$, $a = 3$, $b = \sqrt { 6 }$, $\angle A = \frac { 2 \pi } { 3 }$, then $\angle B =$