jee-main 2014 Q83

jee-main · India · 09apr Standard Integrals and Reverse Chain Rule Definite Integral Evaluation via Substitution or Standard Forms

$\int \frac { \sin ^ { 8 } x - \cos ^ { 8 } x } { \left( 1 - 2 \sin ^ { 2 } x \cos ^ { 2 } x \right) } d x$ is equal to
(1) $- \frac { 1 } { 2 } \sin 2 x + c$
(2) $- \sin ^ { 2 } x + c$
(3) $- \frac { 1 } { 2 } \sin x + c$
(4) $\frac { 1 } { 2 } \sin 2 x + c$

$\int \frac { \sin ^ { 8 } x - \cos ^ { 8 } x } { \left( 1 - 2 \sin ^ { 2 } x \cos ^ { 2 } x \right) } d x$ is equal to\\
(1) $- \frac { 1 } { 2 } \sin 2 x + c$\\
(2) $- \sin ^ { 2 } x + c$\\
(3) $- \frac { 1 } { 2 } \sin x + c$\\
(4) $\frac { 1 } { 2 } \sin 2 x + c$

Paper Questions

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