jee-main 2018 Q69

jee-main · India · 15apr_shift1 Circles Circle Equation Derivation
A circle passes through the points $( 2,3 )$ and $( 4,5 )$. If its centre lies on the line, $y - 4 x + 3 = 0$, then its radius is equal to
(1) $\sqrt { 5 }$
(2) 1
(3) $\sqrt { 2 }$
(4) 2
A circle passes through the points $( 2,3 )$ and $( 4,5 )$. If its centre lies on the line, $y - 4 x + 3 = 0$, then its radius is equal to\\
(1) $\sqrt { 5 }$\\
(2) 1\\
(3) $\sqrt { 2 }$\\
(4) 2