jee-main 2018 Q83

jee-main · India · 15apr_shift1 Integration by Substitution Substitution to Transform Integral Form (Show Transformed Expression)

If $f \left( \frac { x - 4 } { x + 2 } \right) = 2 x + 1 , ( x \in R = \{ 1 , - 2 \} )$, then $\int f ( x ) d x$ is equal to (where $C$ is a constant of integration)
(1) $12 \log _ { e } | 1 - x | - 3 x + c$
(2) $- 12 \log _ { e } | 1 - x | - 3 x + c$
(3) $- 12 \log _ { e } | 1 - x | + 3 x + c$
(4) $12 \log _ { e } | 1 - x | + 3 x + c$

If $f \left( \frac { x - 4 } { x + 2 } \right) = 2 x + 1 , ( x \in R = \{ 1 , - 2 \} )$, then $\int f ( x ) d x$ is equal to (where $C$ is a constant of integration)\\
(1) $12 \log _ { e } | 1 - x | - 3 x + c$\\
(2) $- 12 \log _ { e } | 1 - x | - 3 x + c$\\
(3) $- 12 \log _ { e } | 1 - x | + 3 x + c$\\
(4) $12 \log _ { e } | 1 - x | + 3 x + c$

Paper Questions

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