Let the equations of two sides of a triangle be $3x - 2y + 6 = 0$ and $4x + 5y - 20 = 0$. If the orthocenter of this triangle is at $(1,1)$ then the equation of its third side is:\\
(1) $122y + 26x + 1675 = 0$\\
(2) $26x - 122y - 1675 = 0$\\
(3) $26x + 61y + 1675 = 0$\\
(4) $122y - 26x - 1675 = 0$