Q72
Areas by integration
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Let $A(4,-4)$ and $B(9,6)$ be points on the parabola, $y^2 = 4x$. Let $C$ be chosen on the arc $AOB$ of the parabola, where $O$ is the origin, such that the area of $\triangle ACB$ is maximum. Then, the area (in sq. units) of $\triangle ACB$, is:
(1) 32
(2) $31\frac{3}{4}$
(3) $30\frac{1}{2}$
(4) $31\frac{1}{4}$