If the system of linear equations
$$\begin{aligned}
& x - 2 y + k z = 1 \\
& 2 x + y + z = 2 \\
& 3 x - y - k z = 3
\end{aligned}$$
has a solution $( x , y , z )$, $z \neq 0$, then $( x , y )$ lies on the straight line whose equation is:\\
(1) $4 x - 3 y - 4 = 0$\\
(2) $3 x - 4 y - 4 = 0$\\
(3) $3 x - 4 y - 1 = 0$\\
(4) $4 x - 3 y - 1 = 0$