Given that the slope of the tangent to a curve $y = y ( x )$ at any point $( x , y )$ is $\frac { 2 y } { x ^ { 2 } }$. If the curve passes through the centre of the circle $x ^ { 2 } + y ^ { 2 } - 2 x - 2 y = 0$, then its equation is\\
(1) $x ^ { 2 } \log _ { e } | y | = - 2 ( x - 1 )$\\
(2) $x \log _ { e } | y | = 2 ( x - 1 )$\\
(3) $x \log _ { e } | y | = - 2 ( x - 1 )$\\
(4) $x \log _ { e } | y | = x - 1$