jee-main 2023 Q86

jee-main · India · session1_25jan_shift2 Vectors: Lines & Planes Distance Computation (Point-to-Plane or Line-to-Line)
The shortest distance between the lines $x + 1 = 2 y = - 12 z$ and $x = y + 2 = 6 z - 6$ is
(1) 2
(2) 3
(3) $\frac { 5 } { 2 }$
(4) $\frac { 3 } { 2 }$
The shortest distance between the lines $x + 1 = 2 y = - 12 z$ and $x = y + 2 = 6 z - 6$ is\\
(1) 2\\
(2) 3\\
(3) $\frac { 5 } { 2 }$\\
(4) $\frac { 3 } { 2 }$