jee-main 2023 Q85

jee-main · India · session1_25jan_shift2 Vectors 3D & Lines Vector Algebra and Triple Product Computation

Let $\vec { a } = - \hat { i } - \hat { j } + \hat { k } , \vec { a } \cdot \vec { b } = 1$ and $\vec { a } \times \vec { b } = \hat { i } - \hat { j }$. Then $\vec { a } - 6 \vec { b }$ is equal to
(1) $3 ( \hat { i } - \hat { j } - \widehat { k } )$
(2) $3 ( \hat { i } + \hat { j } + \hat { k } )$
(3) $3 ( \hat { i } - \hat { j } + \widehat { k } )$
(4) $3 ( \hat { i } + \hat { j } - \widehat { k } )$

Let $\vec { a } = - \hat { i } - \hat { j } + \hat { k } , \vec { a } \cdot \vec { b } = 1$ and $\vec { a } \times \vec { b } = \hat { i } - \hat { j }$. Then $\vec { a } - 6 \vec { b }$ is equal to\\
(1) $3 ( \hat { i } - \hat { j } - \widehat { k } )$\\
(2) $3 ( \hat { i } + \hat { j } + \hat { k } )$\\
(3) $3 ( \hat { i } - \hat { j } + \widehat { k } )$\\
(4) $3 ( \hat { i } + \hat { j } - \widehat { k } )$

Paper Questions

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