For $\alpha, \beta \in \mathbb{R}$, suppose the system of linear equations\\
$x - y + z = 5$\\
$2x + 2y + \alpha z = 8$\\
$3x - y + 4z = \beta$\\
has infinitely many solutions. Then $\alpha$ and $\beta$ are the roots of\\
(1) $x^{2} - 10x + 16 = 0$\\
(2) $x^{2} + 18x + 56 = 0$\\
(3) $x^{2} - 18x + 56 = 0$\\
(4) $x^{2} + 14x + 24 = 0$