jee-main 2023 Q80

jee-main · India · session1_30jan_shift2 Integration by Substitution Substitution to Transform Integral Form (Show Transformed Expression)
If $\int \sqrt{\sec 2x - 1}\, dx = \alpha \log_{e}\left|\cos 2x + \beta + \sqrt{\cos 2x\left(1 + \cos \frac{1}{\beta}x\right)}\right| + \text{constant}$, then $\beta - \alpha$ is equal to $\_\_\_\_$. 
If $\int \sqrt{\sec 2x - 1}\, dx = \alpha \log_{e}\left|\cos 2x + \beta + \sqrt{\cos 2x\left(1 + \cos \frac{1}{\beta}x\right)}\right| + \text{constant}$, then $\beta - \alpha$ is equal to $\_\_\_\_$.
Paper Questions
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