jee-main 2024 Q75

jee-main · India · session2_08apr_shift2 Areas by integration
The area of the region in the first quadrant inside the circle $x ^ { 2 } + y ^ { 2 } = 8$ and outside the parabola $y ^ { 2 } = 2 x$ is equal to : (1) $\frac { \pi } { 2 } - \frac { 1 } { 3 }$ (2) $\pi - \frac { 1 } { 3 }$ (3) $\frac { \pi } { 2 } - \frac { 2 } { 3 }$ (4) $\pi - \frac { 2 } { 3 }$
The area of the region in the first quadrant inside the circle $x ^ { 2 } + y ^ { 2 } = 8$ and outside the parabola $y ^ { 2 } = 2 x$ is equal to :
(1) $\frac { \pi } { 2 } - \frac { 1 } { 3 }$
(2) $\pi - \frac { 1 } { 3 }$
(3) $\frac { \pi } { 2 } - \frac { 2 } { 3 }$
(4) $\pi - \frac { 2 } { 3 }$