When the numbers $1, 2, 3, 4, 5, 6, 7$ and 8 are placed in the boxes below such that each box contains a different number, all equalities are satisfied.
$\square : \square = 4$
$\square \times \square = 4$
$\square - \square = 4$
$\square + \square = A$
Accordingly, what is the number A?
A) 7
B) 8
C) 9
D) 10
E) 11