jee-advanced 2000 Q7

jee-advanced · India · screening Differentiating Transcendental Functions Second derivative via implicit differentiation

7. If $x 2 + y 2 = 1$, then :
(A) yy'" - 2(y ' )2+1=0
(B) $y y ^ { \prime \prime } + \left( y ^ { \prime } \right) 2 + 1 = 0$

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(C) $y y \prime \prime = \left( y ^ { \prime } \right) 2 - 1 = 0$
(D) $y y ^ { \prime \prime } + 2 \left( y ^ { \prime } \right) 2 + 1 = 0$

7. If $x 2 + y 2 = 1$, then :\\
(A) yy'" - 2(y ' )2+1=0\\
(B) $y y ^ { \prime \prime } + \left( y ^ { \prime } \right) 2 + 1 = 0$

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(C) $y y \prime \prime = \left( y ^ { \prime } \right) 2 - 1 = 0$\\
(D) $y y ^ { \prime \prime } + 2 \left( y ^ { \prime } \right) 2 + 1 = 0$\\

Paper Questions

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