On the coordinate plane, there is a circle $C _ { 1 } : ( x - 4 ) ^ { 2 } + y ^ { 2 } = 1$. As shown in the figure, a tangent line $l$ with positive slope is drawn from the origin to the circle $C _ { 1 }$, and the point of tangency is called $\mathrm { P } _ { 1 }$.
A circle $C _ { 2 }$ has its center on the line $l$, passes through the point $\mathrm { P } _ { 1 }$, and is tangent to the $x$-axis. Let $\mathrm { P } _ { 2 }$ be the point of tangency between this circle and the $x$-axis.
A circle $C _ { 3 }$ has its center on the $x$-axis, passes through the point $\mathrm { P } _ { 2 }$, and is tangent to the line $l$. Let $\mathrm { P } _ { 3 }$ be the point of tangency between this circle and the line $l$.
A circle $C _ { 4 }$ has its center on the line $l$, passes through the point $\mathrm { P } _ { 3 }$, and is tangent to the $x$-axis. Let $\mathrm { P } _ { 4 }$ be the point of tangency between this circle and the $x$-axis. Continuing this process, let $S _ { n }$ be the area of circle $C _ { n }$. What is the value of $\sum _ { n = 1 } ^ { \infty } S _ { n }$? (Note: The radius of circle $C _ { n + 1 }$ is smaller than the radius of circle $C _ { n }$.) [4 points]
(1) $\frac { 3 } { 2 } \pi$
(2) $2 \pi$
(3) $\frac { 5 } { 2 } \pi$
(4) $3 \pi$
(5) $\frac { 7 } { 2 } \pi$