\textbf{135-} The shortest distance between the two lines $\dfrac{x-1}{3} = -y + 4 = \dfrac{z}{5}$ and $\begin{cases} x = 2 \\ y = 5 \end{cases}$ is which of the following?
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(1) $\dfrac{3}{\sqrt{10}}$ \hfill (2) $\dfrac{4}{\sqrt{10}}$ \hfill (3) $\sqrt{10}$ \hfill (4) $2\sqrt{5}$
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