| (1) $2$ | (2) $4$ | (3) $10^2$ | (4) $10^4$ |
\textbf{224-} For the hypothetical reaction: $\text{M}^+(\text{aq}) + \text{X}^-(\text{aq}) + \text{OH}^-(\text{aq}) \rightarrow \text{MOH}(\text{aq}) + \text{X}^-(\text{aq}) + \text{M}(\text{aq})$, the rate law is:
$$\bar{R} = k[\text{X}][\text{OH}^-]^2$$
By changing the pH of the solution from 10 to 14 (by adding $\text{NaOH(s)}$) and keeping the concentration of $\text{X(aq)}$ constant, the reaction rate becomes how many times?
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(1) $2$ & (2) $4$ & (3) $10^2$ & (4) $10^4$
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