63. In the figure below, three positive point charges at the vertices of an equilateral triangle are fixed. The net electric field at point M (center of the triangle) is $E$. If we remove charge $q_2$, how large does the net electric field at point M become? [Figure: Equilateral triangle with vertices labeled $q_2 = 2\,\mu\text{C}$ (top right), $q_1 = 1\,\mu\text{C}$ (left), $q_3 = 3\,\mu\text{C}$ (bottom), and center point M] (1) $\sqrt{5}$ (2) $2\sqrt{5}$ (3) $\dfrac{3}{2}$ (4) $\dfrac{2}{3}$
\textbf{63.} In the figure below, three positive point charges at the vertices of an equilateral triangle are fixed. The net electric field at point M (center of the triangle) is $E$. If we remove charge $q_2$, how large does the net electric field at point M become?
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\textit{[Figure: Equilateral triangle with vertices labeled $q_2 = 2\,\mu\text{C}$ (top right), $q_1 = 1\,\mu\text{C}$ (left), $q_3 = 3\,\mu\text{C}$ (bottom), and center point M]}
\end{center}
(1) $\sqrt{5}$
(2) $2\sqrt{5}$
(3) $\dfrac{3}{2}$
(4) $\dfrac{2}{3}$
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