\textbf{80--} Regarding the given reaction, which statement is correct?
$$\mathrm{C_2H_4(g) + 6F_2(g) \rightarrow 2CF_4(g) + 4HF(g)}$$
\begin{itemize}
\item[(1)] All atoms in the reactants have reached the noble gas configuration.
\item[(2)] The oxidation number of carbon in the reaction is $-2$ and for it in the product is different.
\item[(3)] This reaction is an example of the formation of polar covalent reactants.
\item[(4)] $\mathrm{CF_4}$ has the greatest number of lone pair electrons among the participating molecules in the reaction.
\end{itemize}
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