Q19. The acceptor level of a p-type semiconductor is 6 eV . The maximum wavelength of light which can create a hole would be : Given $\mathrm { hc } = 1242 \mathrm { eVnm }$. (1) 414 nm (2) 103.5 nm (3) 207 nm (4) 407 nm
Q19. The acceptor level of a p-type semiconductor is 6 eV . The maximum wavelength of light which can create a hole would be : Given $\mathrm { hc } = 1242 \mathrm { eVnm }$.\\
(1) 414 nm\\
(2) 103.5 nm\\
(3) 207 nm\\
(4) 407 nm