Consider the following reaction $\mathrm{Ca} + 2\mathrm{HCl} \rightarrow \mathrm{CaCl}_{2} + \mathrm{H}_{2}$
We have 14 g Ca reacts with excess of HCl. Choose the incorrect option.
(A) Mass produced of $\mathrm{CaCl}_{2}$ is $38.85\mathrm{~g}$
(B) Mole of $\mathbf{H}_{\mathbf{2}}$ produced is $\mathbf{0.35~mol}$
(C) Volume of $\mathrm{H}_{2}$ produced at STP is 7.945
(D) Mass of $\mathrm{CaCl}_{2}$ produced is $\mathbf{3.885}\mathrm{~g}$