$\int _ { 0 } ^ { 36 } \mathbf { f } \left( \frac { \mathbf { t x } } { 36 } \right) \mathbf { d t } = \mathbf { 4 \alpha f } ( \mathbf { x } )$
If the curve represented by $\mathrm { y } = \mathrm { f } ( \mathrm { x } )$ is a standard parabola passing through $( 2,1 )$ and $( - 4 , \beta )$ then find