We consider $f$ the function defined on the interval $] 0 ; + \infty \left[ \right.$ by $f ( x ) = \frac { \mathrm { e } ^ { \sqrt { x } } } { 2 \sqrt { x } }$ and we call $C _ { f }$ its representative curve in an orthonormal coordinate system.
- We define the function $g$ on the interval $] 0 ; + \infty \left[ \operatorname { by } g ( x ) = \mathrm { e } ^ { \sqrt { x } } \right.$.
(a) Show that $g ^ { \prime } ( x ) = f ( x )$ for all $x$ in the interval $] 0 ; + \infty [$.
(b) For all real $x$ in the interval $] 0 ; + \infty \left[ \right.$, calculate $f ^ { \prime } ( x )$ and show that:
$$f ^ { \prime } ( x ) = \frac { \mathrm { e } ^ { \sqrt { x } } ( \sqrt { x } - 1 ) } { 4 x \sqrt { x } }$$
- (a) Determine the limit of the function $f$ at 0.
(b) Interpret this result graphically. - (a) Determine the limit of the function $f$ at $+ \infty$.
(b) Study the direction of variation of the function $f$ on $] 0 ; + \infty [$. Draw the variation table of the function $f$ including the limits at the boundaries of the domain of definition.
(c) Prove that the equation $f ( x ) = 2$ has a unique solution on the interval [ $1 ; + \infty [$ and give an approximate value to $10 ^ { - 1 }$ of this solution. - We set $I = \int _ { 1 } ^ { 2 } f ( x ) d x$.
(a) Calculate $I$.
(b) Interpret graphically the result obtained. - We admit that the function $f$ is twice differentiable on the interval $] 0 ; + \infty [$ and that:
$$f ^ { \prime \prime } ( x ) = \frac { \mathrm { e } ^ { \sqrt { x } } ( x - 3 \sqrt { x } + 3 ) } { 8 x ^ { 2 } \sqrt { x } }$$
(a) By setting $X = \sqrt { x }$, show that $x - 3 \sqrt { x } + 3 > 0$ for all real $x$ in the interval $] 0 ; + \infty [$.
(b) Study the convexity of the function $f$ on the interval $] 0 ; + \infty [$.