csat-suneung 2017 Q10

csat-suneung · South-Korea · csat__math-science 3 marks Variable acceleration (1D) Find velocity/speed by differentiating position

A point P moving on the coordinate plane has position $( x , y )$ at time $t$ $(t > 0)$ given by $$x = t - \frac { 2 } { t } , \quad y = 2 t + \frac { 1 } { t }$$ What is the speed of point P at time $t = 1$? [3 points]
(1) $2 \sqrt { 2 }$
(2) 3
(3) $\sqrt { 10 }$
(4) $\sqrt { 11 }$
(5) $2 \sqrt { 3 }$

A point P moving on the coordinate plane has position $( x , y )$ at time $t$ $(t > 0)$ given by
$$x = t - \frac { 2 } { t } , \quad y = 2 t + \frac { 1 } { t }$$
What is the speed of point P at time $t = 1$? [3 points]\\
(1) $2 \sqrt { 2 }$\\
(2) 3\\
(3) $\sqrt { 10 }$\\
(4) $\sqrt { 11 }$\\
(5) $2 \sqrt { 3 }$

Paper Questions

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