A die is rolled twice. Given that the number 6 does not appear at all, what is the probability that the sum of the two numbers is a multiple of 4? [3 points]\\
(1) $\frac { 4 } { 25 }$\\
(2) $\frac { 1 } { 5 }$\\
(3) $\frac { 6 } { 25 }$\\
(4) $\frac { 7 } { 25 }$\\
(5) $\frac { 8 } { 25 }$