Let $A=\{0,-a\}$, $B=\{1,a-2,2a-2\}$. If $A\subseteq B$, then $a=$ A. 2 B. 1 C. $\frac{2}{3}$
B If $a-2=0$, then $a=2$. At this time, $A=\{0,-2\}$, $B=\{1,0,2\}$, which does not satisfy the condition. If $a=1$, then $A=\{0,-1\}$, $B=\{1,-1,0\}$, which satisfies the requirement. Choose B.
Let $A=\{0,-a\}$, $B=\{1,a-2,2a-2\}$. If $A\subseteq B$, then $a=$\\
A. 2\\
B. 1\\
C. $\frac{2}{3}$