Let the focus of parabola $C: y^2 = 6x$ be $F$. A line through $F$ intersects $C$ at $A$ and $B$. A perpendicular from $A$ to the line $l: x = -\frac{3}{2}$ meets it at $D$. A line through $F$ perpendicular to $AB$ meets $l$ at $E$. Then\\
A. $|AD| = |AF|$\\
B. $|AE| = |AB|$\\
C. $|AB| \geq 6$\\
D. $|AE| \cdot |BE| \geq 18$