If $T$ is a distribution on $\mathcal{D}$, we define the derivative distribution $T'$ by $$\forall \varphi \in \mathcal{D}, \quad T'(\varphi) = -T(\varphi')$$ Justify that $T'$ is a distribution on $\mathcal{D}$.
If $T$ is a distribution on $\mathcal{D}$, we define the derivative distribution $T'$ by
$$\forall \varphi \in \mathcal{D}, \quad T'(\varphi) = -T(\varphi')$$
Justify that $T'$ is a distribution on $\mathcal{D}$.