We denote by $a_{ii}$ for $1 \leqslant i \leqslant n$ the diagonal elements of $A \in \mathcal{S}_{n}(\mathbb{R})$ with ordered spectrum $a = s^{\downarrow}(A)$. Show that, more generally than in 8a, we have for every integer $1 \leqslant j \leqslant n$
$$\sum_{i=1}^{j} a_{ii} \leqslant \sum_{i=1}^{j} a_{i}.$$