We assume $n = 2$. We identify elements $x = \binom { x _ { 1 } } { x _ { 2 } } \in \mathbb { R } ^ { 2 }$ with vectors $\vec { x } = x _ { 1 } \vec { i } + x _ { 2 } \vec { j }$ of the Euclidean plane relative to an orthonormal frame $(\Omega , \vec { i } , \vec { j })$. Let $O$ be the matrix of a rotation with center $\Omega$ and angle $\theta \in ] - \pi , \pi ]$ nonzero. Using a drawing, find two vectors $x _ { + }$ and $x _ { - }$ such that $$O x _ { + } = \operatorname { diag } ( 1 , - 1 ) x _ { + } \text { and } O x _ { - } = \operatorname { diag } ( - 1,1 ) x _ { - }$$ Then discuss according to the sign of $\theta$, which of $x _ { + }$ and $x _ { - }$ is strictly positive.
We assume $n = 2$. We identify elements $x = \binom { x _ { 1 } } { x _ { 2 } } \in \mathbb { R } ^ { 2 }$ with vectors $\vec { x } = x _ { 1 } \vec { i } + x _ { 2 } \vec { j }$ of the Euclidean plane relative to an orthonormal frame $(\Omega , \vec { i } , \vec { j })$.
Let $O$ be the matrix of a rotation with center $\Omega$ and angle $\theta \in ] - \pi , \pi ]$ nonzero. Using a drawing, find two vectors $x _ { + }$ and $x _ { - }$ such that
$$O x _ { + } = \operatorname { diag } ( 1 , - 1 ) x _ { + } \text { and } O x _ { - } = \operatorname { diag } ( - 1,1 ) x _ { - }$$
Then discuss according to the sign of $\theta$, which of $x _ { + }$ and $x _ { - }$ is strictly positive.