With $S _ { 0 } = 1 / 2$, $I _ { 0 } = 1 / 2$, $R _ { 0 } = 0$, and $h : \mathbf { R } _ { + } \rightarrow \mathbf { R }$ defined by $$\forall x \in \mathbf { R } _ { + } \quad h ( x ) = \ln \left( \frac { S ( x ) } { S _ { 0 } } \right) = \ln ( 2 S ( x ) ),$$ show that $h$ is a solution of the Cauchy problem $(C)$: $$( C ) : \left\{ \begin{array} { l } y ^ { \prime } ( x ) + y ( x ) + 1 = \frac { 1 } { 2 } \mathrm { e } ^ { y ( x ) } \\ y ( 0 ) = 0 \end{array} \right.$$ using the relation established in question 18.
With $S _ { 0 } = 1 / 2$, $I _ { 0 } = 1 / 2$, $R _ { 0 } = 0$, and $h : \mathbf { R } _ { + } \rightarrow \mathbf { R }$ defined by
$$\forall x \in \mathbf { R } _ { + } \quad h ( x ) = \ln \left( \frac { S ( x ) } { S _ { 0 } } \right) = \ln ( 2 S ( x ) ),$$
show that $h$ is a solution of the Cauchy problem $(C)$:
$$( C ) : \left\{ \begin{array} { l } y ^ { \prime } ( x ) + y ( x ) + 1 = \frac { 1 } { 2 } \mathrm { e } ^ { y ( x ) } \\ y ( 0 ) = 0 \end{array} \right.$$
using the relation established in question 18.