jee-advanced 2007 Q62

jee-advanced · India · paper1 Conditional Probability Proof of a General Conditional Expectation or Independence Property

Let $E^c$ denote the complement of an event $E$. Let $E$, $F$, $G$ be pairwise independent events with $P(G) > 0$ and $P(E \cap F \cap G) = 0$. Then $P(E^c \cap F^c | G)$ equals
(A) $P(E^c) + P(F^c)$
(B) $P(E^c) - P(F^c)$
(C) $P(E^c) - P(F)$
(D) $P(E) - P(F^c)$

Let $E^c$ denote the complement of an event $E$. Let $E$, $F$, $G$ be pairwise independent events with $P(G) > 0$ and $P(E \cap F \cap G) = 0$. Then $P(E^c \cap F^c | G)$ equals\\
(A) $P(E^c) + P(F^c)$\\
(B) $P(E^c) - P(F^c)$\\
(C) $P(E^c) - P(F)$\\
(D) $P(E) - P(F^c)$

Paper Questions

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