Three students $S _ { 1 } , S _ { 2 }$, and $S _ { 3 }$ are given a problem to solve. Consider the following events:
$U$ : At least one of $S _ { 1 } , S _ { 2 }$, and $S _ { 3 }$ can solve the problem,
$V : S _ { 1 }$ can solve the problem, given that neither $S _ { 2 }$ nor $S _ { 3 }$ can solve the problem,
$W : S _ { 2 }$ can solve the problem and $S _ { 3 }$ cannot solve the problem,
T: $S _ { 3 }$ can solve the problem.

For any event $E$, let $P ( E )$ denote the probability of $E$. If

$$P ( U ) = \frac { 1 } { 2 } , \quad P ( V ) = \frac { 1 } { 10 } , \quad \text { and } \quad P ( W ) = \frac { 1 } { 12 }$$

then $P ( T )$ is equal to

\begin{center}
\begin{tabular}{ | l | l | l | l | l | l | l | l | }
\hline
(A) & $\frac { 13 } { 36 }$ & (B) & $\frac { 1 } { 3 }$ & (C) & $\frac { 19 } { 60 }$ & (D) & $\frac { 1 } { 4 }$ \\
\hline
\end{tabular}
\end{center}